14x^2-36=0

Solution for 14x^2-36=0 equation:

14x^2-36=0

a = 14; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·14·(-36)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*14}=\frac{0-12\sqrt{14}}{28}
=-\frac{12\sqrt{14}}{28}
=-\frac{3\sqrt{14}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*14}=\frac{0+12\sqrt{14}}{28}
=\frac{12\sqrt{14}}{28}
=\frac{3\sqrt{14}}{7}
$